Odpowiedź:
[tex]a)\ \ (3k-5)^2=(3k-5)(3k-5)=9k^2-15k-15k+25=9k^2-30k+25\\\\\\b)\ \ (m+2)(-m-2)-(2-m)(-2-m)=\\\\=-m^2-2m-2m-4-(-4-2m+2m+m^2)=-m^2-4m-4-(-4+m^2)=\\\\=-m^2-4m-4+4-m^2=-2m^2-4m[/tex]
