Odpowiedź :
Siema,
Trzeba tu korzystać w twierdzenia Pitagorasa, więc:
a)
[tex] {8}^{2} + {15}^{2} = {x}^{2} \\ 64 + 225 = {x}^{2} \\ {x}^{2} = 289 \: \: .\sqrt{} \\ x = 17[/tex]
c)
[tex] {14}^{2} + {x}^{2} = {50}^{2} \\ 196 + {x}^{2} = 2500 \\ {x}^{2} = 2304 \\ x = 48[/tex]
b)
[tex] {24}^{2} + {x}^{2} = {51}^{2} \\ 576 + {x}^{2} = 2601 \\ {x}^{2} = 2025 \\ x = 45[/tex]
d)
[tex] {24}^{2} + {70}^{2} = {x}^{2} \\ 576 + 4900 = {x}^{2} \\ {x}^{2} = 5476 \\ x = 74[/tex]
e)
[tex] {x}^{2} + {5}^{2} = {13}^{2} \\ {x }^{2} + 25 = 169 \\ {x}^{2} = 144 \\ x = 12[/tex]
f)
[tex] {x}^{2} + {20}^{2} = {29}^{2} \\ {x}^{2} + 400 = 841 \\ {x}^{2} = 441 \\ x = 21[/tex]
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