Odpowiedź:
[tex]Zad.1\\\\a)\ \ \frac{8^2}{8}=\frac{64}{8}=8\\\\\\b)\ \ \frac{(-2)^7}{2}=\frac{-128}{2}=-64\\\\\\c)\ \ \frac{9}{(-9)^2}=\frac{9}{81}=\frac{1}{9}\\\\\\d)\ \ \frac{-3^4}{27}=\frac{-81}{27}=-3\\\\\\Zad.2\\\\(\frac{2}{3})^4=\frac{2^4}{3^4}=\frac{16}{81}[/tex]
