Odpowiedź:
[tex](5p-1)(p-2)+\frac{1}{3}(6-6p^2-3p)=5p^2-10p-p+2+2-2p^2-p=3p^2-12p+4\\\\\\dla\ \ p=2\\\\3p^2-12p+4=3\cdot2^2-12\cdot2+4=3\cdot4-24+4=12-24+4=16-24=-8[/tex]
