Pole podstawy
[tex]6 \times \frac{{a}^{2} \sqrt{3} }{4} [/tex]
[tex]6 \times \frac{ {4}^{2} \sqrt{3} }{4} = 6 \times \frac{16 \sqrt{3} }{4} = 6 \times 4 \sqrt{3} = 24 \sqrt{3} [/tex]
Objętość
[tex] \frac{24 \sqrt{3} \times 6}{3} = 24 \sqrt{3} \times 2 = 48 \sqrt{3} [/tex]
