Odpowiedź:
[tex]a)\\\\\begin{cases}y=4x-5\\y=x^2-1\end{cases}\\\\\\4x-5=x^2-1\\\\4x-5-x^2+1=0\\\\4x-4-x^2=0\\\\-x^2+4x-4=0\\\\-(x^2-4x+4)=0\\\\-(x-2)^2=0\ \ /\cdot(-1)\\\\(x-2)^2=0\\\\x-2=0\\\\x=2\\\\\\y=4x-5\\\\y=4\cdot2-5=8-5=3\\\\\begin{cases}x=2\\y=3\end{cases}[/tex]
[tex]b)\\\\\begin{cases}y=2x^2+3\\y=-4x+1\end{cases}\\\\\\2x^2+3=-4x+1\\\\2x^2+3+4x-1=0\\\\2x^2+4x+2=0\ \ /:2\\\\x^2+2x+1=0\\\\(x+1)^2=0\\\\x+1=0\\\\x=-1\\\\\\y=-4x+1\\\\y=-4\cdot(-1)+1=4+1=5\\\\\begin{cases}x=-1\\y=5\end{cases}[/tex]
