Odpowiedź:
9.
a)
[tex]\frac{1}{4}x^3-x^2=0\\\frac{1}{4}x^2(x-4)=0\\x_1=0 \\x_2=4[/tex]
b)
[tex]x^3-6x^2+9x=0\\x(x^2-6x+9)=0\\x(x-3)^2=0\\x_1=0\\x_2=3[/tex]
10.
[tex]w(x)=(m+k)x^3-kx+7\\g(x)=10x^3+2x+7\\(m+k)x^3-kx+7 = 10x^3+2x+7\\\left \{ {{k=-2} \atop {m+k=10}} \right. \\m+k=10\\m+(-2)=10\\m-2=10\\m=12\\\\\left \{ {{k=-2} \atop {m=12}} \right.[/tex]
