Odpowiedź :
a]
[tex]3a-5+7a+4-5a+3=3a+7a-5a-5+4+3=\\\\=\boxed{5a+2}=5\cdot(-2)+2=-10+2=\boxed{-8}[/tex]
b]
[tex]5x+3y+8-6x+7y=5x-6x+3y+7y+8=\\\\=\boxed{-x+10y+8}=-2+10\cdot(-0,5)+8=6+(-5)=6-5=\boxed1[/tex]
a]
[tex]3a-5+7a+4-5a+3=3a+7a-5a-5+4+3=\\\\=\boxed{5a+2}=5\cdot(-2)+2=-10+2=\boxed{-8}[/tex]
b]
[tex]5x+3y+8-6x+7y=5x-6x+3y+7y+8=\\\\=\boxed{-x+10y+8}=-2+10\cdot(-0,5)+8=6+(-5)=6-5=\boxed1[/tex]