[tex]6x + 16 > x^{2}\\\\-x^{2}+6x+16 > 0\\\\a = -1, \ b = 6, \ c = 16\\\\\Delta = b^{2}-4ac = 6^{2}-4\cdot(-1)\cdot16 = 36 + 64 = 100\\\\\sqrt{\Delta} = \sqrt{100} = 10\\\\x_1 = \frac{-b+\sqrt{\Delta}}{2a} = \frac{-6+10}{2\cdot(-1)} = \frac{4}{-2} = -2\\\\x_2 = \frac{-b-\sqrt{\Delta}}{2a} = \frac{-6-10}{-2}=\frac{-16}{-2} = 8[/tex]
a < 0, to parabola zwrócona jest ramionami do dołu, wówczas:
[tex]\boxed{x \in (-2; 8)}[/tex]
