Odpowiedź:
[tex]1) \: (2x + 4) \times ( {x}^{2} - 4) = {x}^{3} \times x \\ 2 {x}^{3} - 8x + 4 {x}^{2} - 16 = {x}^{4} \\ - {x}^{4} + 2 {x}^{3} + 4 {x}^{2} - 8x - 16 = 0[/tex]
[tex]2) \: 2x( {x}^{2} - 4) = {x}^{3} \times x \\ 2 {x}^{3} - 8x = {x}^{4} \\ - {x}^{4} + 2 {x}^{3} - 8x = 0[/tex]
