[tex]d)\\(-1.1)^2=(-\frac{11}{10})*(-\frac{11}{10})=\frac{121}{100}=1.21\\(1\frac14)^3=(\frac54)^3=\frac{5^3}{4^3}=\frac{125}{64}=1\frac{61}{64}\\(-2\frac15)^3=(-\frac{11}5)^3=-(\frac{11^3}{5^3})=-\frac{1331}{125}=-10\frac{81}{25}\\1,3^2=\frac{13}{10}*\frac{10}{10}=\frac{169}{100}=1.69\\\\e)\\-3^4=-81\\-(-1,5)^3=(\frac{15}{10})^3=\frac{3375}{1000}=3.375\\-1.1^2=-(\frac{11}{10})^2=-\frac{121}{100}=-1.21\\-(-\frac23)^4=-(\frac23)^4=-\frac{16}{81}[/tex]
[tex]f)\\\frac{2^3}3=\frac83=2\frac23\\\frac{(-3)^2}2=\frac92=4\frac12\\\frac2{3^2}=\frac29\\\frac{-5^3}{(-3)^2}=\frac{-125}9=-13\frac89[/tex]
