[tex](6x + 5 {)}^{2} = 9x(4x + 7) \\ 36 {x}^{2} + 60x + 25 = 36 {x}^{2} + 63x \\ - 3x = - 25 \\ x = \frac{25}{3} [/tex]
[tex](2x - 3 {)}^{2} = (1 + 2x {)}^{2} \\ 4 {x}^{2} - 12x + 9 = 4 {x}^{2} + 4x + 1 \\ - 16x = - 8 \\ x = \frac{8}{16} = \frac{1}{2} [/tex]
[tex](5x + 1)(5x - 1) = (3 - 5x {)}^{2} \\ 25 {x}^{2} - 1 = 25 {x}^{2} - 30x + 9 \\ 30x = 10 \\ x = \frac{10}{30} = \frac{1}{3} [/tex]
