[tex]Dane:\\m = 150 \ kg\\S = 50 \ cm^{2} = 0,005 \ m^{2}\\g = 10\frac{N}{kg}\\Szukane:\\p = ?\\\\Rozwiazanie\\\\p = \frac{F}{S}\\\\F = m\cdot g = 150 \ kg\cdot10\frac{N}{kg} = 1 \ 500 \ N\\\\p = \frac{1500 \ N}{0,005 \ m^{2}}\\\\\boxed{p = 300 \ 000 \ Pa = 300 \ kPa}\\\\(1 \ kPa = 1000 \ Pa)[/tex]
