Rozwiązane

klasa 8.
Potrzebuję tego na teraz daje naj.
bez e, f.​

Klasa 8 Potrzebuję Tego Na Teraz Daje Naj Bez E F class=

Odpowiedź :

Nastusxdviz

a.

[tex]x^{2} =8^{2} +6^{2}[/tex]

[tex]x^{2} =64+36\\x^{2} =100\\x=10[/tex]

b.

[tex]y^{2} =17^{2}-15^{2} \\y^{2}=289-225\\ y^{2}=64\\y^{2}=8[/tex]

c.

[tex]z^{2}=6^{2}+2^{2}\\z^{2}=36+4\\z^{2}=40\\z=\sqrt{40}\\ z=2\sqrt{10}[/tex]

d.

[tex]a^{2}=(3\sqrt{2})^{2}-4^{2}\\ a^{2}=18-16\\a^{2}=2\\a=\sqrt{2}[/tex]

LoczeeQviz

a)

[tex] {8}^{2} + {6}^{2} = {x }^{2} \\ {x}^{2} = 64 + 36 \\ {x}^{2} = 100 \\ x = \sqrt{100} = 10[/tex]

b)

[tex] {y}^{2} + {15}^{2} = {17}^{2} \\ {y}^{2} + 225 = 289 \\ {y}^{2} = 64 \\ y = \sqrt{64} = 8[/tex]

c)

[tex] {2}^{2} + {6}^{2} = {z}^{2} \\ {z}^{2} = 4 + 36 \\ {z}^{2} = 40 \\ z = \sqrt{40} = \sqrt{4 \times 10} = 2 \sqrt{10} [/tex]

d)

[tex] {a}^{2} + {4}^{2} = (3 \sqrt{2} {)}^{2} \\ {a}^{2} + 16 = 9 \times 2 \\ {a}^{2} = 18 - 16 \\ {a}^{2} = 2 \\ a = \sqrt{2} [/tex]

Viz Inne Pytanie