Odpowiedź:
[tex]a)\ \ 2(3p-4)+\frac{4-2p}{2}=6p-8+\frac{\not2(2-p)}{\not2}=6p-8+(2-p)=6p-8+2-p=5p-6\\\\\\b)\ \ 3(2-5m)-\frac{12m+9}{3}=6-15m-\frac{\not3(4m+3)}{\not3}=6-15m-(4m+3)=\\\\=6-15m-4m-3=-19m+3\\\\\\c)\ \ -5(4t-2)-\frac{30t-5}{5}=-20t+10-\frac{\not5(6t-1)}{\not5}=-20t+10-(6t-1)=\\\\=-20t+10-6t+1=-26t+11\\\\\\d)\ \ \frac{6x-14}{2}+\frac{6+15x}{3}=\frac{\not2(3x-7)}{\not2}+\frac{\not3(2+5x)}{\not3}=3x-7+2+5x=8x-5[/tex]
[tex]e)\ \ \frac{12-20y}{-4}+\frac{14-7y}{7}=\frac{\not4(3-5y)}{-\not4}+\frac{\not7(2-y)}{\not7}=-(3-5y)+(2-y)=-3+5y+2-y=\\\\=4y-1[/tex]
