[tex]f(x) = \frac{4x^{2}-16}{(x-2)(2x+1)}\\\\\\\underline{Dziedzina:}\\\\x-2 \neq 0 \ \ \wedge \ \ 2x+1 \neq 0\\\\x\neq 2 \ \ \wedge \ x \neq -\frac{1}{2}\\\\D = R \setminus\{-\frac{1}{2}, 2\}[/tex]
[tex]\underline{Miejsca \ zerowe:}\\\\4x^{2}-16 = 0 \ \ /:4\\\\x^{2}-4 = 0\\\\(x+2)(x-2) = 0\\\\x+2 = 0 \ \ \vee \ \ x-2 = 0\\\\x = -2 \ \ \vee \ \ x = 2 \ \ \notin D\\\\\boxed{x = -2}[/tex]
