bardzo proszę o pomoc daje naj​

Bardzo Proszę O Pomoc Daje Naj class=

Odpowiedź :

[tex]a)\\\\1,25*(- 3\frac{1}{4})*(-8) =\frac{125}{100}*(- \frac{13}{\not{4}^1})*(-\not{8}^2)=\frac{5}{\not{4}^2}*\not{26}^{13}=\frac{65}{2}=37\frac{1}{2}[/tex]

[tex]b)\\\\ -3*(4,2-6,3)=-3 *(-2,1)=6,3\\\\\\c)\\\\(3\frac{2}{3} -4)*(6-\frac{3}{5})=-\frac{1}{3}*5\frac{2}{5}=-\frac{1}{3}*\frac{27}{5}=-\frac{27}{15}=-\frac{9}{5}=-1\frac{4}{5}[/tex]

[tex]d)\\\\(- 3\frac{4}{5} - \frac{1}{5})*(-3,7+1,4)=(- 3\frac{5}{5} )*(-2,3) =(-4)*(-2,3)=9,2\\\\\\e)\\\\(0,92-5):(3*0,4)=-4,08:1,2=-3,4[/tex]

[tex]f)\\\\(- 5\frac{1}{7}-\frac{9}{14} ):(-1+\frac{17}{35})=(- 5\frac{2}{14}-\frac{9}{14} ):(- \frac{ 18}{35})=(- \frac{72}{14}-\frac{9}{14} )*(- \frac{35}{ 18})=\\\\=(-\frac{81}{\not{14}^2})*(-\frac{\not{35}^5}{18})=\frac{405}{36}=\frac{45}{4}=11\frac{1}{4}[/tex]

[tex]g)\\\\(1\frac{1}{6}- 5\frac{3}{4} )*(-12):1,1=(1\frac{2}{12}- 5\frac{9}{12} )*(-12):\frac{11}{10}=(-4\frac{7}{12})*(-12)*\frac{10}{11}=\\\\=(- \frac{\not{55}^5}{\not{12}^1})*(-\not{12}^1)*\frac{10}{\not{11}^1}= 50\\\\\\h)\\\\(-\frac{2}{3})^2*(-12,3+3,3)^2=\frac{4}{9} *(-9)^2=\frac{4}{\not{9}^1}* \not{81}^9 = 36[/tex]

[tex]i)\\\\(-0,3)^3:(-1+ \frac{2}{5})^2=(-\frac{3}{10})^3:(-\frac{3}{5})^2=(-\frac{27}{1000}):\frac{9}{25}=(-\frac{\not{27}^3}{\not{1000}^{40}})*\frac{\not{25}^1}{\not{9}^1}= -\frac{3}{40}[/tex]

[tex]j)\\\\(2,5-2\frac{1}{3})^2-(- \frac{1}{3})^3 :\frac{2}{3}=(2 \frac{5}{10}-2\frac{1}{3})^2-(- \frac{1}{ 27}) *\frac{3}{2}=\\\\= (2 \frac{1}{2}-2\frac{1}{3})^2-(- \frac{1}{ \not{27}^9}) *\frac{\not{3}^1}{2}=(2 \frac{3}{6}-2\frac{2}{6})^2+\frac{1}{18} =(\frac{1}{6})^2+\frac{1}{18}=\\\\=\frac{1}{36}+\frac{2}{36}= \frac{3}{36}=\frac{1}{12}[/tex]