Szczegółowe wyjaśnienie:
[tex]a = 16cm \\ h = \frac{a \sqrt{3} }{2} = \frac{16 \sqrt{3} }{2} = 8 \sqrt{3} \\ r = \frac{1}{3}h = \frac{1}{3} \times 8 \sqrt{3} = \frac{8 \sqrt{3} }{3} \\obw = 2 \: \pi \: r = \frac{16\pi \sqrt{3} }{3} \\ R = \frac{2}{3} \times h = \frac{2}{3} 8 \sqrt{3} = \frac{16 \sqrt{3} }{3} \\ obw = 2\pi \: R = \frac{32\pi \sqrt{3} }{3} \\ suma \: \\ \frac{16\pi \sqrt{3} }{3} + \frac{32\pi \sqrt{3} }{3} = \frac{48\pi \sqrt{3} }{3} = 16\pi \sqrt{3} [/tex]
