[tex]dane:\\m = 5 \ kg\\F_{w} = 11\frac{2}{3} \ N = \frac{35}{3} \ N\\szukane:\\a = ?[/tex]
Z II zasady dynamiki:
[tex]a = \frac{F_{w}}{m}\\\\a = \frac{\frac{35}{3} \ N}{5 \ kg} = \frac{\frac{35}{3} \ kg\cdot\frac{m}{s^{2}}}{5 \ kg}\\\\\underline{a = \frac{7}{3}\frac{m}{s^{2}} = 2\frac{1}{3}\frac{m}{s^{2}}=2,(3)\frac{m}{s^{2}}\approx2,3\frac{m}{s^{2}}}[/tex]
Odp. Przyspieszenie tego ciała a ≈ 2,3 m/s².
