Odpowiedź:
[tex]a^{0}=1[/tex]
[tex]25^{0}+\frac{18^{0} }{60} + 15*\frac{1^{0} }{3600} = 1+\frac{1}{60}+\frac{15}{3600} = 1+\frac{1}{60} +\frac{1}{240} = 1 + \frac{4}{240} + \frac{1}{240} = 1+\frac{5}{240} = 1\frac{1}{48}[/tex]
