[tex]Dane:\\m = 60 \ kg\\h =40 \ cm = 0,4 \ m\\t = 3 \ s\\g = 10\frac{N}{kg}\\Szukane:\\W = ?\\P = ?[/tex]
Rozwiązanie
Praca:
[tex]W = E_{p} = mgh\\\\W = mgh\\\\W = 60 \ kg\cdot10\frac{N}{kg}\cdot0,4 \ m\\\\\boxed{W = 240 \ J}[/tex]
Moc:
[tex]P = \frac{W}{t}\\\\P = \frac{240 \ J}{3 \ s}\\\\\boxed{P = 80 \ W}[/tex]