Odpowiedź :
[tex]zad.6\\\\P_{rownolegloboku} =0,396~dm^{2} =39,6~cm^{2} \\\\a=3,6~cm\\h-wysokosc~~rownolegloboku\\\\P_{rownolegloboku} =a\cdot h ~~\Rightarrow ~~h=\dfrac{P_{rownolegloboku} }{a} \\\\h=\dfrac{39.6~cm^{2} }{3,6~cm} =11~cm\\\\Odp:~~Wysokosc~~wynosi~~11~cm.[/tex]
[tex]zad.7\\\\Dane:\\\\a=8,4[j]\\b=5,4[j]\\h_{a} =18[j]\\h_{b} =?\\\\P_{rownolegloboku_a} =a\cdot h_{a}\\\\P_{rownolegloboku_b} =b\cdot h_{b}\\\\P_{rownolegloboku_a} =P_{rownolegloboku_b}\\\\P_{rownolegloboku_a} =8,4\cdot 1,8 ~[j^{2} ]=15,12~[j^{2} ]\\\\P_{rownolegloboku_b} =5,4~[j]\cdot h_{b}\\\\5,4~[j]\cdot h_{b}=15,12~[j^{2} ]~~\mid \div 5,4~[j]\\\\h_{b}=\dfrac{ 15,12~[j^{2} ]}{5,4~[j] } \\\\h_{b}=2,8~[j]\\\\\\Odp:~~Wysokosc~~poprowadzona~~do~~krotszego~~boku~~wynosi ~~2,8~[j].[/tex]