Odpowiedź:
zad. 5
P1 = 2400 W
t1 = 4 min
P2 = 1500 W
t2 = 1 min
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W ?
P = P1 +P2 = 2400 + 1500 = 3900 W = 3,9 kW
t = t1 + t2 = 4 + 1 = 5 min = 5*60s = 300 s = 300/3600 h = 1/12 h
W = P*t = 3900W * 300 s = 1 170 000 J = 1,17 MJ
W = P*t = 3,9kW * 1/12 h = 3,9/12 kWh = 0,325 kWh
zad. 6
Ib = 6A
U = 12V
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Pmax ?
Pmax = Ib * U = 6A*12V = 72 W
Pmax = 72 W
Wyjaśnienie:
