Dane:
m = 300 dag = 3 kg
F₁ = 12 N (←)
F₂ = 24 N (→)
Fw = F₂ - F₁ = 24 N - 12 N = 12 N
Szukane:
a = ?
Rozwiązanie
Z II zasady dynamiki Newtona:
[tex]a = \frac{F_{w}}{m}\\\\a = \frac{12 \ N}{3 \ kg}\\\\\boxed{a = 4\frac{N}{kg} = 4\frac{m}{s^{2}}}[/tex]
