Odpowiedź:
a) 0= -0,5x+1
-1= -0,5x
2= x
b) założenie: x>=0
x^2-2=0
x^2=2
[tex] \sqrt{ {x}^{2} } = \sqrt{2 } \\ x = \sqrt{2 } [/tex]
c)
[tex] \frac{2x + 7}{5} = 0 \\ 2x + 7 = 0 \\ 2x = - 7 \\ x = - 3.5[/tex]
d)
[tex]0 = \sqrt{x - 2} \\ 0 = x - 2 \\ x = 2[/tex]
e)
[tex] \frac{1}{4} x - \frac{2}{3 } = 0 \\ \frac{1}{4} x = \frac{2}{3} \\ \\ x = \frac{2}{3} \times 4 \\ x = 2 \frac{2}{3} [/tex]
f)
[tex] \frac{ - 3x + 1}{3} = 0 \\ - 3x + 1 = 0 \\ - 3x = - 1 \\ x = \frac{1}{3} [/tex]
