[tex](7- 5\frac{2}{5})* \frac{1}{4}=1\frac{3}{5})* \frac{1}{4}= \frac{\not{8}^2}{5} * \frac{1}{\not{4}^1}=\frac{2}{5}[/tex]
[tex](\frac{4}{9} -\frac{47}{72} )* \frac{4}{5}=(\frac{32}{72} -\frac{47}{72} )* \frac{4}{5}=(-\frac{\not{15}^3}{\not{72}^ {18}})*\frac{\not{4}^1}{\not{5}^1}= -\frac{3}{18}=-\frac{1}{6}[/tex]
[tex]6*(1\frac{1}{3})^2= 6*(\frac{4}{ 3})^2=\not{6}^2*\frac{16}{\not{9}^3}=\frac{32}{3}=10\frac{2}{3}[/tex]
[tex]( \frac{5}{7})^2:\frac{5}{7}=\frac{\not{25}^5}{\not{49}^7}*\frac{\not{7}^1}{\not{5}^1}=\frac{5}{7}[/tex]
[tex](\frac{1}{3}-\frac{1}{4})^2=(\frac{4}{12}-\frac{3}{12})^2= (\frac{1}{12})^2=\frac{1}{144}[/tex]
[tex]( \frac{2}{5})^2+ 4\frac{1}{2} * 2\frac{2}{3}= \frac{4}{25} + \frac{\not{9}^3}{\not{2}^1} * \frac{\not{8}^4}{\not{3}^1}=\frac{4}{25}+12=12\frac{4}{25}[/tex]
[tex]5*( \frac{1}{2})^2+15*( \frac{1}{3})^2 =5*\frac{1}{4}+\not{15}^5*\frac{1}{\not{9}^3}= \frac{5}{4}+\frac{5}{3}=\frac{15}{12}+\frac{20}{12}=\frac{35}{12}=2\frac{11}{12}[/tex]
[tex]\frac{1}{9} -(\frac{5}{6}-\frac{2}{3})^2=\frac{1}{9}-(\frac{5}{6}-\frac{4}{6})^2=\frac{1}{9}-(\frac{1}{6})^2=\frac{1}{9}- \frac{1}{36} =\frac{4}{36}- \frac{1}{36} =\frac{3}{36}=\frac{1}{12}[/tex]
