[tex]Dane:\\m = 6 \ kg\\S = 0,002 \ m^{2}\\g = 10\frac{N}{kg}\\Szukane:\\p = ?\\\\Rozwiazanie\\\\p = \frac{F}{S}\\\\ale \ \ F = m\cdot g = 6 \ kg\cdot10\frac{N}{kg} = 60 \ N\\\\p = \frac{60 \ N}{0,002 \ m^{2}}\\\\\boxed{p = 30 \ 000 \ Pa = 30 \ kPa}\\\\(1 \ kPa = 1000 \ Pa)[/tex]
