[tex]Dane:\\m = 2 \ kg\\r = 1 \ m\\T = 2 \ s\\Szukane:\\a_{r} = ?[/tex]
Rozwiązanie
[tex]a_{r} = \frac{v^{2}}{r} \ \ i \ \ v = \frac{2\pi r}{T}\\\\a_{r} = \frac{(\frac{2\pi r}{T})^{2}}{r}\\\\a_{r}= \frac{4\pi^{2} r}{T^{2}}\\\\a_{r} = \frac{4\cdot3,14^{2}\cdot1 \ m}{(2 \ s)^{2}}=9,8596\frac{m}{s^{2}}\\\\\boxed{a_{r}\approx9,86\frac{m}{s^{2}}}[/tex]
