7x-3≤2x²
2x²-7x+3≥0
Δ=(-7)²-4·2·3 =49-24=25
√Δ=√25=5
x₁=[tex]\frac{7-5}{4}=\frac{1}{2}[/tex] lub x₂=[tex]\frac{7+5}{4}=3[/tex]
x ∈ (-∞; [tex]\frac{1}{2}[/tex]> ∪ <3; +∞)
