Odpowiedź:
[tex]\dfrac{\sqrt{2}}{\sqrt{3}+2}=\dfrac{\sqrt{2}}{\sqrt{3}+2}\cdot\dfrac{\sqrt{3}-2}{\sqrt{3} -2}=\dfrac{\sqrt{2}(\sqrt{3}-2)}{(\sqrt{3}+2)(\sqrt{3}-2)}=\dfrac{\sqrt{6}-2\sqrt{2}}{(\sqrt{3})^2-2^2}=\dfrac{\sqrt{6}-2\sqrt{2}}{3-4}=\\\\\\=\dfrac{\sqrt{6}-2\sqrt{2}}{-1}=-(\sqrt{6}-2\sqrt{2})=-\sqrt{6}+2\sqrt{2}=2\sqrt{2}-\sqrt{6}[/tex]
