Odpowiedź:
[tex]a)\\\\(x+2)(2-x)=6x-x^2\\\\2x-x^2+4-2x=6x-x^2\\\\-x^2+4=6x-x^2\\\\-x^2-6x+x^2=-4\\\\-6x=-4\ \ /:(-6)\\\\x=\frac{4}{6}\\\\x=\frac{2}{3}\\\\\\b)\\\\(x+2)^2-(3-x)^2=5\\\\x^2+4x+4-(9-6x+x^2)=5\\\\x^2+4x+4-9+6x-x^2=5\\\\10x-5=5\\\\10x=5+5\\\\10x=10\ \ /:10\\\\x=1[/tex]
