[tex]Dane:\\h = 1,6 \ m\\d = 0,998\frac{g}{cm^{3}} = 998\frac{kg}{m^{3}}\\g = 10\frac{m}{s^{2}}=10\frac{N}{kg}\\Szukane:\\p = ?\\\\p = d\cdot g\cdot h\\\\p = 998\frac{kg}{m^{3}}\cdo10\frac{N}{kg}\cdot1,6 \ m\\\\\boxed{p = 15 \ 968 \ Pa = 15,968 \ kPa}\\\\1 \ kPa = 1000 \ Pa[/tex]
