Odpowiedź :
p%: "p" z "x" to: "p:x * 100%"
Zadanie 4a
[tex]p\%=55:(2^3\cdot5^2)\cdot100\%=55:(8\cdot25)\cdot100\%=\frac{55}{800}\cdot100\%=6,875% [/tex]
Zadanie 4b
[tex]p\%=12:(\sqrt[4]{16}\cdot5^2)\cdot100\%=12: (2\cdot25)\cdot100\%=\frac{12}{50} \cdot100\%=24\%[/tex]
Zadanie 4c
[tex]p\%=0,2:(\sqrt[3]{64}\cdot5^4)\cdot100\%=\frac{20}{4\cdot5^4} \%=\frac{4\cdot5}{4\cdot5^4} \% =\frac{1}{5^3}\%= \frac{1}{125}\% [/tex]