Zad 1 str 97 Matematyka z plusem klasa 5 podręcznik
Proszę pomóżcie daje 75

Odpowiedź:
zad 1)
[tex]\frac{4}{5}:2=\frac{4}{5}:\frac{x}{y}:\frac{2}{1}=\frac{4}{5}*\frac{1}{2}=\frac{4}{10}=0,4[/tex]
[tex]\frac{2}{7}:3=\frac{2}{7}:\frac{3}{1}=\frac{2}{7}*\frac{1}{3}=\frac{2}{21} [/tex]
[tex]\frac{4}{7}:2=\frac{4}{7}:\frac{2}{1}=\frac{4}{7}*\frac{1}{2}=\frac{2}{7} [/tex]
[tex]\frac{5}{9}:3=\frac{5}{9}:\frac{3}{1}=\frac{5}{9}*\frac{1}{3}=\frac{5}{27} [/tex]
[tex]1\frac{1}{2}:3=\frac{3}{2}:\frac{3}{1}=\frac{3}{2}*\frac{1}{3}=\frac{1}{2}=0,5[/tex]
[tex]2\frac{1}{4}:6=\frac{9}{4}:\frac{6}{1}=\frac{9}{4}*\frac{1}{6}=\frac{3}{8} [/tex]
[tex]4\frac{1}{5}:7=\frac{21}{5}:\frac{7}{1}=\frac{21}{5}*\frac{1}{7}=\frac{3}{5}=0,6[/tex]
[tex]2\frac{4}{7}:9=\frac{18}{7}:\frac{9}{1}=\frac{18}{7}*\frac{1}{9}=\frac{2}{7} [/tex]
[tex]20\frac{2}{3}:31=\frac{62}{3}:\frac{31}{1}=\frac{62}{3}*\frac{1}{31}=\frac{2}{3} [/tex]
[tex]10\frac{1}{5}:9=\frac{51}{5}:\frac{9}{1}=\frac{51}{5}*\frac{1}{9}=\frac{51}{45} [/tex]
[tex]10\frac{2}{11}:21=\frac{112}{11}:\frac{21}{1}=\frac{112}{11}*\frac{1}{21}=\frac{112}{231} [/tex]
[tex]1\frac{1}{99}:15=\frac{100}{99}:\frac{15}{1}=\frac{100}{99}*\frac{1}{15}=\frac{20}{297} [/tex]
Szczegółowe wyjaśnienie: