1.
[tex] \frac{2}{3} + \frac{1}{5} = \frac{10}{15} + \frac{3}{15} = \frac{13}{15} [/tex]
[tex] \frac{5}{6} - \frac{3}{4} = \frac{10}{12} - \frac{9}{12} = \frac{1}{12} [/tex]
[tex] \frac{7}{20} - \frac{1}{4} = \frac{7}{20} - \frac{5}{20} = \frac{2}{20} = \frac{1}{10} [/tex]
2.
[tex]5 \frac{1}{4} - 2 \frac{1}{6} = 5 \frac{3}{12} - 2 \frac{2}{12} = 3 \frac{1}{12} [/tex]
[tex]4 \frac{1}{3} + 2 \frac{1}{6} = 4 \frac{2}{6} + 2 \frac{1}{6} = 6 \frac{3}{6} = 6 \frac{1}{2} [/tex]
[tex]4 \frac{1}{2} - 1 \frac{3}{4} = 4 \frac{2}{4} - 1 \frac{3}{4} = 3 \frac{6}{4} - 1 \frac{3}{4} = 2 \frac{3}{4} [/tex]
3.
[tex]1 \frac{3}{4} - \frac{1}{3} = 1 \frac{9}{12} - \frac{4}{12} = 1 \frac{5}{12} [/tex]
Odpowiedź: W dzbanku zostało 1 5/12 l soku
Myślę że pomogłem ;)
