[tex]\frac{2x+3}{4}= \frac{x+7}{3} |*12 \\ 12(\frac{2x+3}{4} )=12(\frac{x+7}{3} )\\ 3(2x+3)=4(x+7)\\ 6x+9=4x+28|-4x\\ 2x+9= 28|-9\\ 2x=19 |:2\\ x =\frac{19}{2} \\ x = 9\frac{1}{2} [/tex]
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