Zad. 7
[tex](7-5\frac25)*\frac14=(6\frac55-5\frac25)*\frac14=1\frac35*\frac14=\frac85*\frac14=\frac25*\frac11=\frac25[/tex]
[tex](\frac79-\frac{47}{72}):1\frac14=(\frac{56}{72}-\frac{47}{72}):\frac54=\frac9{72}*\frac45=\frac9{18}*\frac15=\frac12*\frac15=\frac1{10}[/tex]
[tex]6*(1\frac13)^2=6*(\frac43)^2=6*\frac{16}9=2*\frac{16}3=\frac{32}3[/tex]
[tex](\frac57)^2:\frac57=\frac57 - \text{bo }(\frac57)^2:\frac57=(\frac57)^{2-1}=(\frac57)^1=\frac57)\\\text{lub nie na skroty}\\(\frac57)^2:\frac57=\frac{25}{49}*\frac75=\frac{5}{7}*\frac{1}{1}=\frac57[/tex]
[tex](\frac13-\frac14)^2=(\frac{4}{12}-\frac{3}{12})^2=(\frac1{12})^2=\frac1{144}[/tex]
[tex](\frac25)^2+4\frac12*2\frac23=\frac4{25}+\frac92*\frac83=\frac4{25}+\frac{3}{1}*\frac{4}{1}=\frac4{25}+3*4=\frac4{25}+12=12\frac4{25}[/tex]
[tex]5*(\frac12)^2+15*(\frac13)^2=5*\frac14+15*\frac19=\frac54+\frac{15}9=\frac{45}{36}+\frac{60}{36}=\frac{105}{36}=2\frac{33}{36}=2\frac{11}{12}[/tex]
[tex]\frac19-(\frac56-\frac23)^2=\frac19-(\frac56-\frac{4}{6})^2=\frac19-(\frac16)^2=\frac19-\frac1{36}=\frac{4}{36}-\frac1{36}=\frac3{36}=\frac1{12}[/tex]
