[tex]Dane:\\m = 1 \ kg\\T_1 = 5^{o}C\\T_2 = 10^{o}C\\\Delta T = T_2 - T_1 = 10^{o}C - 5^{o}C = 5^{o}C\\c = 840\frac{J}{kg\cdot^{o}C}\\Szukane:\\Q = ?\\\\Q = m\cdot c \cdot \Delta T\\\\Q = 1 \ kg\cdot840\frac{J}{kg\cdot^{o}C}\cdot5^{o}C\\\\\boxed{Q = 4 \ 200 \ J = 4,2 \ kJ}\\\\(1 \ kJ = 1000 \ J)[/tex]
Odp. Trzeba dostarczyć 4,2 kJ ciepła.
