Odpowiedź:
[tex]\huge\boxed{\boxed{\text{wynik}\longrightarrow2\frac{2}{3}}}[/tex]
Szczegółowe wyjaśnienie:
[tex](2\frac{2}{3}-\frac{4}{5})\cdot1\frac{3}{7}=(2\frac{2\cdot5}{3\cdot5}-\frac{4\cdot3}{5\cdot3})\cdot\frac{1\cdot7+3}{7}=(2\frac{10}{15}-\frac{12}{15})\cdot\frac{7+3}{7}=\\\\=(1\frac{25}{15}-\frac{12}{15})\cdot\frac{10}{7}=1\frac{13}{15}\cdot\frac{10}{7}=\frac{1\cdot15+13}{15}\cdot\frac{10}{7}=\frac{15+13}{15}\cdot\frac{10}{7}=\frac{\not28^4}{\not15_3}\cdot\frac{\not10^2}{\not7_1}=\frac{8}{3}=2\frac{2}{3}[/tex]
