Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]1)\\-5a+(6a-2b+7) = -5a + 6a - 2b + 7= a-2b+7\\\\2)\\(-4n+5m)+(6m+7n)= -4n+5m+6m+7n=3n+11m\\\\3)\\(-3ab+4b-6b)-(3ab-7a+8b)=-3ab+4b-6b-3ab+7a-8b=-3ab-3ab+4b-6b-8b+7a=-6ab-10b+7a\\\\4)\\-(2x+2y)-z-(-5x-3y+3z)=-2x-2y-z+5x+3y-3z=3x+y-4z\\[/tex]
5)
[[tex]{4+1-2a-(-4a+46-6)[/tex]]=[tex]5-2a+4a-40=-35+2a[/tex]
6)
[tex]\frac{4}{7a} +(-(\frac{4}{10} -1a)-b-(\frac{2}{7b}-a) )=\frac{4}{7a}+(-\frac{4}{10} -1a-b-\frac{2}{7b}+a)=\frac{4}{7a}-\frac{4}{10} -1a-b-\frac{2}{7b}+a=\frac{4}{7a} -1a+a-b-\frac{2}{7b}-\frac{4}{10}=\frac{4}{7a}-b-\frac{2}{7b}-\frac{4}{10}[/tex]
7)
[tex]-3\sqrt{2x^{2} }+2x^{2} y-2xy+\sqrt{2x^{2} } -6xy=2x^{2} y-2\sqrt{2x^{2} }-8xy[/tex]
8) jest lub bo nie wiem co ten ukośnik miał znaczyć
[tex]1.8xy^{2} +6.2x\x^{2} y-5.8x^{2} y^{2}+0.35yx^{2} -3.25y^{2} x =1.8y^{2}x +6.2x\x^{2} y-5.8x^{2} y^{2}+0.35x^{2}y -3.25y^{2} x =6.55x^2y-1.45y^2x-5.8x^2y^2 \\lub\\1.8xy^{2} +6.2x y-5.8x^{2} y^{2}+0.35yx^{2} -3.25y^{2} x =1.8y^{2}x +6.2xy-5.8x^{2} y^{2}+0.35x^{2}y -3.25y^{2} x =-5.8x^2y^2-1.45y^2x+0.35x^2y+6.2xy[/tex]
9)
[tex]\frac{4}{9x}-\frac{2}{3y}-\frac{1}{3x} +\frac{2}{15y} =\frac{4}{9x} -\frac{1*3}{3x*3} -\frac{2*5}{3y*5} +\frac{2}{15y} =\frac{4-3}{9x}+ \frac{-10+2}{15y} =\frac{1}{9x} -\frac{8}{15y}[/tex]
10)
[tex]6\sqrt{3} xy-3.2x^{2} +\sqrt{3} xy-7\sqrt{3}x-2.8x^{2} =7\sqrt{3}xy-6x^{2} -7\sqrt{3} x[/tex]
