BLAGAM SZYBKO DAJE NAJ​

BLAGAM SZYBKO DAJE NAJ class=

Odpowiedź :

[tex]a)\\\\4^9*(\frac{1}{8})^9:(\frac{1}{2})^9=(\not{4}^1*\frac{1}{\not{8}^2}:\frac{1}{2})^9 =(\frac{1}{2}*2)^9=1^9=1[/tex]

[tex]b)\\\\ \frac{(\frac{1}{5})^9:(\frac{4}{25})^9}{1,25^8}=\frac{(\frac{1}{5}:\frac{4}{25})^9}{(\frac{125}{100})^8}=\frac{(\frac{1}{\not{5}^1}*\frac{\not{25}^5}{4})^9}{(\frac{5}{4})^8}=\frac{(\frac{5}{4})^9 }{(\frac{5}{4})^8}=(\frac{5}{4})^{9-8}=(\frac{5}{4})^1=\frac{5}{4}=1\frac{1}{4}[/tex]