(2x+2)²>=(3x-2)(2x-3)
4x²+8x+4>=3x²-9x-2x+6
x²+19x-2>=0
Δ=369 √Δ=19,2
x1=(-19-19,2)/2=-19,1
x1=(-19+19,2)/2=0,1
x∈(-niesk;-19,1]∨[0,1 ; +niesk)
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(2x+3)²+4=0
brak rozwiazania L>0
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4x⁴+7x²-2=0
u=x²
4u²+7u-2=0
Δ=81 √Δ=9
u1=(-7-9)/8=-2
u2=(-7+9)/8=1/4
x²=1/4----->x1=1/2 x2=-1/2