Odpowiedź:
a)
[tex]3 \sqrt{5 } + 4 \sqrt{5} [/tex]
To
[tex]7 \sqrt{5} [/tex]
Bo 3+4 to 7
b)
[tex] \sqrt{33} \times \sqrt{3 \frac{2}{3} } = \sqrt{33} \times \sqrt{ \frac{11}{3} } = \sqrt{ \frac{33}{1} \times \frac{11}{3} } = \sqrt{11 \times 11 } = 11[/tex]
c)
[tex] \sqrt{300} - 7 \sqrt{3} = \sqrt{3 \times 10 \times 10} - 7 \sqrt{3} = 10 \sqrt{3} - 7 \sqrt{3} = 3 \sqrt{3} [/tex]
d)
[tex]3 \sqrt{6} \times \frac{1}{2} \sqrt{2} = \frac{3}{1} \times \frac{1}{2} \sqrt{2 \times 2 \times 3} = \frac{3}{2} \sqrt{2 \times 2 \times 3} = \frac{3}{2} \times \frac{2}{1} \sqrt{3} = 3 \sqrt{3} [/tex]
e)
[tex]{( \frac{4 \sqrt{6} }{3} ) }^{2} = \frac{4 \times 6}{3} = \frac{4 \times 2}{1} = 8[/tex]
