Odpowiedź:
[tex]f(x)=-2x^2+x+1\\\Delta=1-4*(-2)=9\\\sqrt\Delta=3\\x_1=\frac{-1-3}{2*(-2)} =\frac{-4}{-4}=1\\ x_2=\frac{-1+3}{2*(-2)} =\frac{2}{-4}=-0,5\\\\f(x)=-x^2+3\\g(x)=(-(x+2)^2+3-2\\g(x)=(-(x^2+4x+4)+1\\g(x)=-x^2-4x-4+1\\g(x)=-x^2-4x-3\\\\a^2=(4\sqrt2)^2-(2+\sqrt3)^2\\a^2=32-(4+4\sqrt3+3)\\a^2=32-4\sqrt3-7\\a^2=25-4\sqrt3\\a=\sqrt{25-4\sqrt3}\\\\obw=4\sqrt2+2+\sqrt3+\sqrt{25-4\sqrt3}\\[/tex]
Szczegółowe wyjaśnienie:
