Odpowiedź:
a)
A = ( 1 , 4 ) , B = (9 , 8)
xa = 1 , xb =9 ,ya = 4 , yb = 8
S - środek odcinka = (xs , ys)
xs = (xa + xb)/2 = (1 + 9)/2 = 10/2 = 5
ys = (ya + yb)/2 = ( 4 + 8)/2 = 12/2 = 6
S = ( 5 , 6 )
IABI - długość odcinka = √[(xb - xa)² + (yb - ya)²] = √[(9 - 1)² + (8 - 4)²] =
= √(8² + 4²) = √(64 + 16) = √80 = √(16 * 5) = 4√5
b)
A = (0 , 2 ) , B = ( 6 , 10 )
xa = 0 , xb = 6 , ya = 2 , yb = 10
S = (xs , ys)
xs = (xa + xb)/2 = (0 + 6)/2 = 6/2 = 3
ys = (ya + yb)/2 = (2 + 10)/2 = 12/2 = 6
S = ( 3 , 6 )
IABI = √[(xb - xa)² + (yb - ya)²] = √[(6 - 0)² + (10 - 2)²] = √(6² + 8²) =
= √(36 + 64) = √100 = 10
