Odpowiedź:
[tex]A.\\\\\sqrt[3]{100}\cdot\sqrt[3]{10}=10\\\\\sqrt[3]{100\cdot10}=10\\\\\sqrt[3]{1000}=10\\\\10=10\\\\L=P\\\\\\B.\\\\\sqrt[3]{-\frac{5}{4}}\cdot\sqrt[3]{-\frac{25}{2}}=\frac{5}{2}\\\\\sqrt[3]{-\frac{5}{4}\cdot(-\frac{25}{2})}=\frac{5}{2}\\\\\sqrt[3]{\frac{125}{8}}=\frac{5}{2}=\frac{5}{2}=\frac{5}{2}\\\\L=P[/tex]
[tex]C.\\\\\sqrt[3]{6,4}\cdot\sqrt[3]{100}=80\\\\\sqrt[3]{6,4\cdot100}=80\\\\\sqrt[3]{640}=80\\\\\sqrt[3]{64\cdot10}=80\\\\4\sqrt[3]{10}=80\\\\L\neq P\\\\\\D.\\\\\sqrt[3]{0,1}\cdot\sqrt[3]{0,01}=0,1\\\\\sqrt[3]{0,1\cdot0,01}=0,1\\\\\sqrt[3]{0,001}=0,1\\\\0,1=0,1\\\\L=P\\\\Odp.C[/tex]
