[tex]3\dfrac{3}{4}-2\dfrac{2}{3}+6-3\dfrac{5}{6} = 3\dfrac{9}{12}-2\dfrac{8}{12}+6-3\dfrac{10}{12} = 9\dfrac{9}{12}-5\dfrac{18}{12}=9\dfrac{9}{12}-6\dfrac{6}{12}= 3\dfrac{3}{12} = 3\dfrac{1}{4}[/tex]
