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[tex](2\cdot\frac{1}{4}+3\cdot0,4+1,6)\cdot\frac{2}{5}=(\frac{1}{2}+1,2+1,6)\cdot\frac{2}{5}=\\\\=(\frac{5}{10}+2,8)\cdot\frac{2}{5}=(0,5+2,8)\cdot\frac{2}{5}=3,3\cdot\frac{2}{5}=\\\\=3\frac{3}{10}\cdot\frac{2}{5}=\frac{3\cdot10+3}{10}\cdot\frac{2}{5}=\frac{30+3}{10}\cdot\frac{2}{5}=\frac{33}{\not10_5}\cdot\frac{\not2^1}{5}=\frac{33}{25}=1\frac{8}{25}[/tex]
