W obu zadaniach zastosujemy twierdzenie Pitagorasa
2.
a)
[tex] {8}^{2} + {17}^{2} = {x}^{2} \\ 64 + 289 = {x}^{2} \\ 353 = {x}^{2} \\ x = \sqrt{353} [/tex]
b)
[tex]0.3^{2} + {5}^{2} = x ^{2} \\ 0.09 + 25 = {x}^{2} \\ 25.09 = {x}^{2} \\ x = \sqrt{25.09} [/tex]
c)
[tex] {14}^{2} + 0.5 ^{2} = {x}^{2} \\ 196 + 0.25 = {x}^{2} \\ {x}^{2} = 196.25 \\ x = \sqrt{196.25} [/tex]
3.
a)
[tex] {3}^{2} + {6}^{2} = {x}^{2} \\ 9 + 36 = {x}^{2} \\ {x}^{2} = 45 \\ x = \sqrt{45} = \sqrt{9 \times 5} = 3 \sqrt{5} [/tex]
b)
[tex] (\sqrt{19} )^{2} + ( \sqrt{19} ) ^{2} = {x}^{2} \\ 19 + 19 = {x}^{2} \\ {x}^{2} = 38 \\ x = \sqrt{38}[/tex]
Myślę że pomogłem ;)
