Odpowiedź:
zad. 2
a) d = 5 x [tex]\sqrt{2}[/tex] = 5[tex]\sqrt{2}[/tex]
b) d = 2[tex]\sqrt{2}[/tex] x [tex]\sqrt{2}[/tex] = 4
c) d = [tex]\sqrt{11}[/tex] x [tex]\sqrt{2}[/tex] = [tex]\sqrt{22}[/tex]
zad. 3
a) a[tex]\sqrt{2}[/tex] = 6
a = [tex]\frac{6}{\sqrt{2} }[/tex] = 6[tex]\sqrt{\frac{2}{2} }[/tex] = 3[tex]\sqrt{2}[/tex]
b) a[tex]\sqrt{2}[/tex] = [tex]\sqrt{3}[/tex]
a = [tex]\frac{\sqrt{3} }{\sqrt{2} }[/tex] = [tex]\sqrt{\frac{6}{2} }[/tex]
c) a[tex]\sqrt{2}[/tex] = 7[tex]\sqrt{2}[/tex]
a = 7
